Electronics

       From the assigned by the head of the group responsible for electronics of automatic robot which automatic robot must follow the map page, it is placed for the competition of my group. Automatic Robot have components of each section such as

                       1. Microcontroller Circuit

                       2. DC Motor Drive Circuit

                       3. Receiver Signal Circuit

                       4. Sensor Circuit

                       5. Digital Circuit

                       6. Power supply and charge circuit

        Which components of each section must be connect to each section but before we will build automatic robot, we must find the information about each section and programming support.

        Which programming can be simulation of microcontroller circuit and each section used in automatic robot such as

                      1. Program Protel 99 SE SP6

                      2. Program Protel DXP

                      3. Program Altium Designer

                      4. Program Pspice

       Which program of each program can be simulated, analyzed, calculated and building layer circuit on PCB( Printed Circuit Board ).

        From assignment, I find data and information of each section to take the concept and application with automatic robot.

                     1. Microcontroller Circuit, I must to find information and data of circuit which I must design the circuit myself, this circuit must be used interface with Microcontroller Device or I find Microcontroller Board, which it can support with programming language of programmer and interface with other devices.

                     2. DC Motor Drive Circuit, I must to find data and information of DC motor drive circuit which automatic robot of my group must forward, rearward, turn right, turn lift and rotate itself, which I use H-Bridge Motor Drive circuit. H-Bridge Motor Drive can cause motor rotation and used for control DC Motor     

                    3. Receiver Signal Circuit, I must to design circuit about receiver signal which automatic robot of my group must receiver signal from manual robot to order to the arm to keep the orange and to put the orange on collection basket.

                    4. Sensor Circuit, I need to study multiple sensor types in the group now because we do not know which is the sensor will be fit. Before design the sensor circuit, you should to study from previous datasheet to determine the length of the capture of the sensor such as TCRT5000 is sensor that uses infrared light to reflect and appropriate for the robot to follow a line.

                   5. Digital Circuit, IC, I need to learn and use the IC which each IC is different option. Digital Circuit a duty to control the operation of the automatic robot which is an important part. I need to use the program to assist in the design circuit because I must to make a small and workable.

                  6. Power supply and charge circuit, I must to study about IC for power supply circuit and form of circuit for design circuit which this circuit need to be in charge themselves when plugs on at 220 volt and must be able to calculate the time when to charge full battery.

         From the assigned by the head of the group responsible for electronics of automatic robot which automatic robot must follow the map page, it is placed for the competition of my group. This week, I find the detail of each part and IC for each part and to find datasheet contains the design circuit.

 

           DC Drive Motor Section, I used to DC Drive Motor is the H-Bridge circuit which can control the motor rotation is free but DC Drive Motor circuit generally very large circuit and require some devices into control a motor which I think that I should select IC for DC Drive Motor to reduce the size of the circuit and I can control the motor rotation. I will use IC TA7279P for drive dc motor because it easy to use, IC number TA7279P is IC for DC Drive Motor Circuit which have characteristics different from general IC drive motor is function “Break” when I sent logic 11 into IC drive motor and IC TA7279P device can be control up to 2 DC Motor which received voltage from 0 to 18 V and output to circuit at current 1.0A (AVE), 3.0A (PEAK). TA7279P to bring you nothing complicated and it does not need as many devices to use but can be work alone itself. In addition, within IC have functions to break working when overheat, and current limit.

 (robot) 20091018_29200.jpg

 

 

TA7279P, DC Drive Motor Circuit

 

       Which I must connect capacitor 10uF for by part noise into the DC Drive Motor Circuit.

 

IN

OUT

MODE

1

2

1

2

0

0

High - Impedance

Stop

0

1

L

H

CW / CCW

1

0

H

L

CCW / CW

1

1

H

H

Break

 

         From the table that will be interesting to work in 2 mode are stop and break which many people may think that 2 mode with the same, motor is not rotation, but it really different.

       STOP – motor disconnect from source which will gradually slow down and stop close.

       BREAK – the motor will be try to stop it.

        Sensor Section, sensor number TCNT1000 using track line which it is reflective optical sensor with transistor output which into the sensor has a radiation or symbol of LED lamp, light is sent out to strike the floor, and then reflected back to the photo transistor when floor is white. If light is black which sensor will be reflected light is a few. Then calculate the resistance which will be limited the voltage of the transmitter and receiver.

            -Transmitter, must see the value to the Forward current, Forward voltage graph and set voltage from source to Vcc and use KVL in principle, and calculated value for resistor.

            -Receiver, must see the value for the Collector current, Collector emitter voltage by a graph which uses 2 statuses Saturated at capture white and cut off when handing black. Resistors are calculating from Saturated than also must see that the distance from the floor sensor signals.

(robot) 20091018_29210.jpg

 

Sensor, TCRT5000

(robot) 20091018_29220.jpg

 

Schematic of Sensor

Calculate Schematic of Sensor

From graph, Collector Current and Forward Current

(robot) 20091018_29510.jpg

  

Set, V+ = 5V, IF = 10mA and IC = 1mA.

            R1 = 5V/1mA = 5k?

            R2 = 5V/10mA = 500?

             

         Power Supply and Charger  Section, Power Supply circuit of automatic robot will be divided into 2 parts is DC Drive Motor Circuit and Drive electronics circuit which will be divided into 5 V and 12 V. 5 V will be used for service in electronics circuit of automatic robot. 12V will be used for service in DC Drive Motor circuit of automatic robot. And current and voltage will be come from all battery 12V which we can be regulated voltage to the rest equal 5V by IC regulator number LM7805. Proposition and the competitive robot must be able charge battery by itself when I plug in the AC electricity and it can open circuit when voltage level is less than a battery can work to prevent damage which I use IC number LM324 into compare voltage level of battery and automatic robot can be charged battery by use a diode connect with battery which defend the current reverse.

 

        Position Sensor of Automatic Robot

 (robot) 20091018_29701.jpg

 

        From the assigned by the head of the group responsible for electronics of automatic robot which automatic robot must follow the map page, it is placed for the competition of my group. This week, I design circuit and calculate voltage and current for sensor circuit, Torque of DC Motor and charge battery circuit, calculate circuit and simulation circuit by Proteus Programming.

 

       Sensor Circuit Section

(robot) 20091018_29711.jpg

 

Sensor Detect Line

Set;      IF = 10mA, IC = 0.1mA,

VCE, sat = 0.4V, VCE = 5V and VF = 1.25V

Which length detect = 12mm from datasheet

Calculate;        R1 and R2

                        R1 = (robot) 20091018_34328.jpg = 375

                        R2 = (robot) 20091018_34338.jpg = 46k

            Therefore, when sensor does not detect white line, Vsensor will be equal 5V or VCE of TCRT5000. But when sensor does detect white line, Vsensor will be equal 0V because VCE of TCRT5000 will bias current to ground which Vsensor will be equal 0V and I use Vref = 2.5V

(robot) 20091018_29720.jpg

 

        Sensor Detect Basket

              I used TSUS4300 and TEFT4300 which TSUS4300 is IR emitter diode and TEFT4300 is infrared phototransistor NPN because TSUS4300 is a high efficiency infrared emitting diode and have low forward voltage, and TEFT4300 is high speed and high sensitive silicon NPN and match with TSUS4300 infrared emitter.

 

 

Calculate;        R3 and R4

Set;      IF = 37mA and VF = 1.3V at 25    C for TSUS4300

                                                R1 (robot) 20091018_30317.jpg100

Set;      IC = 1mA, VCE = 5V and VCE, sat = 0.3V at 25    C for TEFT4300

                                                R2 (robot) 20091018_30326.jpg4700

                        Therefore, when sensor does not detect basket, Vsensor will be equal 5V or VCE of TEFT4300. But when sensor does detect basket, Vsensor will be equal 0V because VCE of TEFT4300 will bias current to ground which Vsensor will be equal 0V.

(robot) 20091018_30286.jpg

 

NE555 for frequency 38 kHz

Calculate for frequency 38 kHz

Set;      f = 38 kHz, Duty Cycle = 70% and Cext = 0.001µF

Calculate;        R1 and R2

                        T = (robot) 20091018_30335.jpg =  26.3µF

                        70% =  (robot) 20091018_30342.jpg

                       

                        (robot) 20091018_34461.jpg

                        R2 = (robot) 20091018_30351.jpg 11,368

                        R1 =  (robot) 20091018_30360.jpg- R2 =  (robot) 20091018_30369.jpg= 15,159

 

 

 

 (robot) 20091018_30297.jpg

  

TSOP4838

Calculation of IR Remote Receiver module (TSOP4838)

Set;      IF = 1.5mA and VF = 2V

            R3 =  (robot) 20091018_30378.jpg= 2k

(robot) 20091018_30308.jpg

 (robot) 20091018_30963.jpg

 

Spec DC Motor

Calculate; Torque and Power of Dc motor

Automatics Robot has 3-wheel which each wheel is balance for all.

Set; Weight of automatic robot = 1.1Kg, µ = 1 and g = 9.81(robot) 20091018_31392.jpg

Calculate the weight of automatic robot to each wheel = (robot) 20091018_31400.jpg

Ffriction = µmg =  (robot) 20091018_31408.jpg= 3.59N

  

(robot) 20091018_31416.jpg

P = (robot) 20091018_31425.jpg0.18W

V = (robot) 20091018_31436.jpg

            Therefore, when compare between torque of stall state of dc motor and torque from calculate that torque of dc motor of stall can be win torque of calculate from automatic robot which automatic robot can be forward and revert with velocity equal 0.147 .(robot) 20091018_31392.jpg

             From the assigned by the head of the group responsible for electronics of automatic robot which automatic robot must follow the map page, it is placed for the competition of my group. This week, I design circuit and calculate voltage and current charge battery circuit calculate circuit and simulation circuit by Proteus Programming and design PCB of each circuit by Protel 99SE Programming

 

Charger Circuit

(robot) 20091018_31485.jpg

 

 Calculate charger circuit

Transformer 12  ;

             (robot) 20091018_31448.jpg

           

           

Fuse

            The regulator can supply the max current to 1.5A per one. This circuit uses two regulators, the max current are 3A.

From the ideal transformer

            (robot) 20091018_31458.jpg

           

           

            We select the fuse 0.5A

Calculate Vo and Vcharge from R1 and R2

            Set ;     R1 = 220

                        R2 = 2.2k

                        Vref = 1.25V

                        Iadj = 50uA

            Formula of Vo;           Vo = Vref +IadjR2

                                                Vo = 1.25(1+ )+(50u)(2.2k)

                                                Vo = 13.86 V 

            Find Vcharge;             Vcharge = Vo - VD

                                                Vcharge = 13.86 – 0.7

                                                Vcharge = 13.16 V.

Calculate Icharge =?

            Set;      Rs = 1?

            Formula of Icharge;    Icharge =  (robot) 20091018_32676.jpg+ Iadj            when Iadj = 50uA ≈ 0A

                                                Icharge = (robot) 20091018_32689.jpg + 0

                                                Icharge = 1.25A

Calculate time for charge battery

            Formla of time;           t = (robot) 20091018_32701.jpg

                                                t = (robot) 20091018_32711.jpg

                                                t = 3.84h

So time to charge will be equal to 3.84 hour when the charge by current 1.25A.

 

From the assigned by the head of the group responsible for electronics of automatic robot which automatic robot must follow the map page, it is placed for the competition of my group. This week, I design circuit and calculate voltage and current for sensor circuit, DC-motor drive circuit, disconnect circuit, charge battery circuit, calculate circuit and simulation circuit by Proteus Programming.

 

Sensor Circuit Section

(robot) 20091018_32942.jpg

 

TCRT5000

            I used TCRT5000 for track line of automatic robot which has sensing distance 12 mm and have a photo transistor and LED IR into the same.

Calculate,        R1 and R2

                        From graph; IF = 10mA, IC = 1mA, VF = 1.1V and VCE = 1V

                        Formula;    (robot) 20091018_32721.jpg     

                                                R1 =(robot) 20091018_32731.jpg = 390

                                                R2 =   (robot) 20091018_32746.jpg = 4k

                        Therefore, TCRT5000 used all current equal 11mA per each

 

TSUS4300 and TEFT4300

(robot) 20091018_32954.jpg

I used TSUS4300 and TEFT4300 which TSUS4300 is IR emitter diode and TEFT4300 is infrared phototransistor NPN because TSUS4300 is a high efficiency infrared emitting diode and have low forward voltage, and TEFT4300 is high speed and high sensitive silicon NPN and match with TSUS4300 GaAs infrared emitter

Calculate,        R3 and R4

                        From datasheet; IF = 37mA and VF = 1.3V at 25    ?C for TSUS4300

                                                R3(robot) 20091018_32756.jpg 100

                        From datasheet; IC = 3.2mA and VCE = 0.3V at 25    ?C for TEFT4300

                                                R4 (robot) 20091018_32756.jpg1468? ≈ 1.5k

                        Therefore, TSUS4300 and TEFT4300 are used all current equal 40.1mA per each

 

 (robot) 20091018_32966.jpg

TSOP4838

I used TSOP4838 is receiver frequency signal at 38kHz from manual robot send to order to keep orange to basket which frequency signal 38kHz come from IC number NE555 create frequency 38kHz  into manual robot

Calculate,        R5

                        From datasheet; IF = 1.1mA

                                    R5 =  4545? ≈ 4.5k

                        Therefore, TSOP4838 used all current equal 1.1mA per each

 

DC-Motor Drive Circuit Section

(robot) 20091018_30308.jpg

 

DC Motor with Gear

 (robot) 20091018_32989.jpg

L293D and DC Motor Gear Circuit

            I used IC number L293D for all drive DC Motor in circuit which L293D have output current capability per channel equal 600mA and DC-motor for moving automatic robot need current equal 600mA for drive motor which matching between L293D and DC Motor.

            DC Motor with gear have speed motor equal 40 r/min, torque equal 0.120 N.m and output equal 0.6w

 

Calculation all the current in circuit

            1. Sensor for track line using the current equal 11mA per item.

            2. Sensor for track basket using the current equal 40.1mA per item.

3. Photo Transistor for 38 kHz using the current equal 1.1mA.

4. DC-Motor and IC drive motor using the current equal 600mA per channel.

            I total = 4(sensor line) +2(sensor basket) +Phototransistors +2(Drive Motor)

                        I total = 4(11mA) +2(40.1mA) +1.1mA +2(600mA)

                        I total = 44mA +80.2mA +1.1mA +1200mA

                        I total = 1325.3mA

  

Battery Charger Section

(robot) 20091018_33000.jpg

 

Transformer 12

(robot) 20091018_32785.jpg

           

             Output voltage from bridge diode at point A and B when disconnect the capacitor C1and C2

            (robot) 20091018_32799.jpg

             Voltage at point A and B when connect the capacitor C1 and C2

            (robot) 20091018_32815.jpg

           

           

           

            We select C 0.1uF       16V or 25V

Fuse

            The regulator can supply the max current to 1.5A per one. This circuit uses two regulators, the max current are 3A.

From the ideal transformer

                         

               We select the fuse 0.5A

 

 

               Disconnect Power Supply by transistor section

 

 (robot) 20091018_33012.jpg

 

Calculate,        R1 and R5

                        From datasheet of LED Light; VF = 2.2V and IF = 10mA

                                    Formula; (robot) 20091018_32848.jpg

                                    R5 = (robot) 20091018_32858.jpg = 930

                                    R5 ≈ 1k

                                    I select R5 equal 1k

                        From datasheet of BD139; VCE = 0.5V, IC = 1.5A and β = 40

                                    IB = (robot) 20091018_32868.jpg = 37.5mA

                                    R1 =  (robot) 20091018_32877.jpg= 293

                                    R1 ≈ 300

                                    I select R1 equal 300

 

          Disconnect Power Supply by relay section

 

 (robot) 20091018_33023.jpg

From datasheet,

JV12KT;         P = 300mW and R coil = 480

            LED Light;     VF = 2.2V and IF = 10mA

            BD139;                       VCE = 0.5V and β = 40        

Calculate, R4 and IC

                        R4 = (robot) 20091018_32887.jpg = 980

                        R4 ≈ 1k

                        IC =  (robot) 20091018_32897.jpg

                        IC = (robot) 20091018_32918.jpg= 0.023A

Power at IC,    P = IV

                        P = 0.023 X 12

                        P = 276 mW

                        So, IC have power equal 276 mW which compare with datasheet of nominal power coil are less than

Voltage across R5 equal 3.84V by measure

                        IB =(robot) 20091018_32928.jpg = 38.4 mA

 

 

 

 

Advertising Zone    Close

ด้วยความปราถนาดีจาก "สยามทูเว็บดอทคอม" และเพื่อป้องกันการเปิดเว็บไซต์เพื่อหลอกลวงขายของ โปรดตรวจสอบร้านค้าให้แน่ใจก่อนตัดสินใจซื้อของทุกครั้งนะคะ    อ่านเพิ่มเติม ...